Let x be the amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train. Suppose that the density curve is as pictured below (a uniform distribution):

(a) What is the probability that x is less than 11 min? more than 14 min? P (x is less than 11 minutes) = P (x is more than 14 minutes) =

(b) What is the probability that x is between 8 and 13 min? P (x is between 8 and 13 minutes) =

(c) Find the value c for which P(x < c) = .8. c = mins You may need to use the appropriate table in Appendix A to answer this question.

a) P (x is less than 11 minutes) =  0.55

P (x is more than 14 minutes) = 0.3

b) P (x is between 8 and 13 minutes) = 0.25

c)  P(x < c) =0.8 is 0.05 x c = 0.8

Step-by-step explanation:

a) P (x is less than 11 minutes) = 11 x 0.05

                                                 = 0.55

P (x is more than 14 minutes) = 0.05 x (20 - 14)

                                                = 0.05 x 6

                                                = 0.3

b) P (x is between 8 and 13 minutes) = 0.05 x (13 -8)

                                                            = 0.05 x 5

                                                             = 0.25

c)  P(x < c) =0.8

The area between 0 and c is 0.8

Hence,

0.05 x c = 0.8

v = 1/3 a^2h

step-by-step explanation:

the volume is 1/3 a^2h.