In triangle ABC, B = 50°, the length of side AB is 8 cm and the length of side BC is 5. Find the length of side AC using the law of cosines.

AC = 6.13000744...

Step-by-step explanation:

The law of cosines is:

= + - 2ab(cosC)

The triangle can be drawn as attached and the numbers can be substituted into the law of cosines, switching the letters:

= + - 2(5)(8)(cos50º)

Then, some numbers can be simplified:

= 89 - 80cos50º

Finally, the square root can be taken to solve for b (side AC):

b = 6.13000744...

Sample answer for Edmentum and Plato

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The length of side AC is approximately equal to 6.13 cm.

Step-by-step explanation:

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

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