The function h(t)=16t^+40t models the height in feet of a ball t seconds after it is thrown into the air. What is the maximum height the ball reaches after it is thrown?

The maximum height is 25 feet

Step-by-step explanation:

The correct question is

The function h(t)=-16t^2+40t models the height in feet of a ball t seconds after it is thrown into the air. What is the maximum height the ball reaches after it is thrown?

we have

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The y-coordinate of the vertex represent the maximum height that the ball reaches

Convert the quadratic equation in vertex form

Factor -16

simplify

Complete the square

Rewrite as perfect squares

The vertex is the point (1.25,25)

therefore

The maximum height is 25 feet

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

about 0.75 hours

step-by-step explanation: