H(t)=(t+3)
2
+5h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plus, 5
What is the average rate of change of hhh over the interval -5\leq t\leq -1−5≤t≤−1minus, 5, is less than or equal to, t, is less than or equal to, minus, 1?

0

Step-by-step explanation:

h(t) = (t + 3)² + 5, -5 ≤ t ≤ -1

The average rate of change is the change in h over the change in t.

(h(-1) − h(-5)) / (-1 − (-5))

= ((-1 + 3)² + 5 − ((-5 + 3)² + 5)) / (-1 + 5)

= (4 + 5 − 4 − 5)) / 4

= 0

answer: d. $20

step-by-step explanation:

just took the test

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05