A sample of 100 clients of an exercise facility was selected. Let X = the number of days per week that a randomly selected client uses the exercise facility. X Frequency 0 3 1 15 2 31 3 27 4 10 5 7 6 7 Find the number that is 1.5 standard deviations BELOW the mean. (Round your answer to three decimal places.)

-5.053

Step-by-step explanation:

For complete calculation see the attachment:

mean= (0 +3+1+15+2+31+3+27+4+10+5+7+6+7)/14= 8.6429 or 9 days

standard deviation= √(∑(X-mean)²/N)

9.1309 or 9 days

1.5 standard deviation= 9.1309× 1.5= 13.6963

number 1.5 standard deviation below the mean= 8.6429-13.7= -5.053

1.30

step-by-step explanation:

the cost of the pair of pants is $31.95