The height of a cylindrical tank is 9.5 feet. The diameter of this tank 1.5 feet longer than the height. The tank was holding water at full capacity, but someone consumed one-seventh of the water. Which is closest to the volume of the remaining water in the tank?

774 cubic feet of water is remaining in the tank

Step-by-step explanation:

In this question, we are asked to calculate the remaining volume in cylindrical tank given that someone consumed 1/7 of its capacity.

Firstly, we need to calculate the capacity in terms of volume of the cylindrical tank.

Since it is a cylinder, we will use the volume of a cylinder.

Mathematically, volume of a cylinder V ;

V = pi * r^2 * h

Where h represents height; 9.5 feet in this case

radius r is diameter d/2 ; we were made to know that diameter of the tank is 1.5 feet longer than the tank. This means the diameter of the tank will be 9.5 + 1.5 = 11 feet. The radius of the tank is thus 11/2 = 5.5 feet

The volume V is thus;

V= 22/7 * 5.5^2 * 9.5

V = 903 cubic feet approximately

Since 1/7 of the tank is consumed, what will remain will be 6/7

This means what is remaking will be 6/7 * 903 = 774 cubic feet

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.