Stewart, ch14.2, find the limit. Since y = 0 for all points on this path, then we have Similarly, approaching along the y-axis yields a limit equal to 0. Since these two limits are the same, we will examine another approach path. Approach (0, 0) along the curve y = x^2. When x is positive, we have When x is negative, we haveSimilarly, approaching along the y-axis yields a limit equal to 0. Since these two limits are the same, we will examine another approach path. Approach (0, 0) along the curve y = x2. When x is positive, we have lim (x, y) → (0, 0) xy x2 + y2 = lim x → 0 x x2 + x4 = lim x → 0 x2 . When x is negative, we have lim (x, y) → (0, 0) xy x2 + y2 = lim x → 0 x x2 + x4 = lim x → 0 x2 − 0 .