Now suppose Joyce doesn't have population standard deviation (perhaps because these are new machines); she only has her sample standard deviation which is 12. Using the same information, (500 grams average, sample mean of 495, sample size of 24), what are the results of Joyce's analysis? (Check all that apply.) You will need to use one of the tables available on Blackboard (knowing which one is part of the question).a. Fail to reject the null hypothesis.
b. Reject the null hypothesis at 90% confidence.
c. Reject the null hypothesis at 95% confidence.
d. Reject the null hypothesis at 99% confidence.

Step-by-step explanation:

The null hypothesis will be that the there is no difference between the sample mean and the average of 500

H₀: μ₀ = 500

The alternative hypothesis would be that there is a difference between the sample mean and the average of 500

Hₐ: μ₀ ≠ 500

This is a two tailed hypothesis test. We can use the t-test for this problem

Test statistic

t = (x - μ) ÷ (σ/√n)

x = 495

μ = 500

σ = 12

n = 24

t = (495 - 500) ÷ (12/√24) = -2.04

Checking the t-distribution table at confidence levels of 90%, 95% and 99%

p-value =

Hope this Helps!!!

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

probability for j is 1/4

while

a is 1/6