Jaime is wanting to go on a cruise. A 3rd class ticket costs $50.99. A 2nd class ticket costs $12.39 less than 3rd class. A 1st class ticket costs 2x as much as 2nd and 3rd classes combined. How much is 1st class costing? Which is a better option for Jamie?

$179.18 ; Second class ticket

Step-by-step explanation:

The first step you want to do is set up the problem.

3rd) 50.99

2nd) 50.99-12.39= x

1st) 2(x+50.99)= y

From there, you subtract 50.99-12.39, which will give you 38.60. That is the cost of the 2nd class ticket.

Plug in the numbers into the final formula:

2(38.60+50.99)= 179.18.

That is the answer for the first question.

This leaves you with the third class ticket costing, $50.99, the second class ticket costing $38.60, and the first class ticket costing $179.18. The better option is the second class ticket.

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: