You have a bag of marbles with 10 green marbles and 12 black marbles. What is the probability that you pick a black marble on the first try. Do not replace that marble and pick a green marble on the second try?

6/11 and 10/21

Step-by-step explanation:

A bag of marbles has 10 green marbles and 12 black marbles. The probability of picking a black marble on the first try will be:

Green marbles= 10

Black marbles= 12

Total marbles= 12+10 = 22

Probability of picking a black marble = 12/22 = 6/11

If the marble is not replace, the probability of picking a green marble on the second try will be:

Green marbles= 10

Black marbles= 12-1= 11

Total marbles= 10+11= 21

Probability of picking a green marble= 10/21

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!