Https://docs. google. com/forms/d/e/1FAIpQLSfFWe1btkNYO2o 3gUl86mRnVNAS-UYZTLXLyV6B3ijPlq5miQ /viewform

can anyone copy and paste this into google and tell me the answers, ill mark brainiest! plz and thx

yeah, but you have to put your own last name, and first name

Step-by-step explanation:

I hope this helps

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.