A line has a slope of 2 and passes through the point (1,3) write an equation in slope intercept form

slope intercept form: y=

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

You know:

m = 2       So substitute/plug it into the equation

y = mx + b

y = 2x + b     To find b, plug in the point (1, 3) into the equation, then isolate/get the variable "b" by itself in the equation

3 = 2(1) + b     Subtract 2 on both sides to get "b" by itself

3 - 2 = 2 - 2 + b

1 = b

y = 2x + 1

The answer to your question is  y = 2x + 1

Step-by-step explanation:

Data

slope = m = 2

Point = (1, 3)

Process

To solve this problem, just substitute the values in the equation slope-intercept form.

x1 = 1     y1 = 3

-Substitution

                    y - y1 = m(x - x1)

                    y - 3 = 2(x - 1)

-Expand

                    y - 3 = 2x - 2

-Simplify

                         y = 2x - 2 + 3

-Result

                         y = 2x + 1

huh? im pretty sure it is in 199

step-by-step explanation: