Mathematics, 08.04.2020 01:32 Levantine2643
When the weight of an object equals the weight of the water displaced (or pushed away) by the object, the object is neutrally buoyant and easy to lift to the surface. A tanker made of 2.5\times10^3\text{ m}^32.5×10 3 m 3 2, point, 5, times, 10, cubed, start text, space, m, end text, cubed of steel sank to the bottom of the ocean. The density of steel is approximately 8\times10^3\text{ kg/m}^38×10 3 kg/m 3 8, times, 10, cubed, start text, space, k, g, slash, m, end text, cubed. The density of seawater is approximately 1\times10^3\text{ kg/m}^31×10 3 kg/m 3 1, times, 10, cubed, start text, space, k, g, slash, m, end text, cubed. Because gravity is pretty much the same everywhere on earth, the weight of the tanker can be assumed to be approximately equal to its mass. In cubic meters, what total volume of seawater needs to be displaced in order to lift the tanker to the surface?
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When the weight of an object equals the weight of the water displaced (or pushed away) by the object...
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