Find the z-score corresponding to the given value and use the z-score to determine whether the value is unusual. Consider a score to be unusual if its z-score is less than -2.00 or greater than 2.00. Round the z-score to the nearest tenth if necessary. A weight of 220 pounds among a population having a mean weight of 161 pounds and a standard deviation of 23.5 pounds Group of answer choices

The z-score is 2.5106 which is an unusual value of z-score as it is greater than 2.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 161 pounds

Standard Deviation, σ = 23.5 pounds

x = 220 pounds

Formula:

Putting values, we get,

Thus, the z-score is 2.5106 which is an unusual value of z-score as it is greater than 2.00

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐