I’ve been stuck on this for 3 hours and got 4 different answers...

Question: Find the exterior perimeter of the shape below. (hint: do not count the line in the middle of the shape)

Step-by-step explanation:

The sides for the square are equal to 2x-5 because that is the square root of the area.  The length of the rectangle is 3x+6 and the width is 3x-6 because that is what you get when you factor the equation.

Now, you have add them up.

To take out the line in the middle of the shape we will subtract because we are assuming that this equation is equal to the shorter side.  This makes the equation

If you are looking for a numerical answer, I can't say I know how to get it.

Hope this helps! <3

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.