A rubber ball dropped on a hard surface takes a sequence of bounces, each one 1/6 as high as the preceding one. If this ball is dropped from a height of 12 feet, how far will it have traveled when it hits the surface the fifth time?

Step-by-step explanation:

GIVEN: A rubber ball dropped on a hard surface takes a sequence of bounces, each one as high as the preceding one.

TO FIND: If this ball is dropped from a height of feet, how far will it have traveled when it hits the surface the fifth time.

SOLUTION:

once the ball is dropped on hard surface it bounces of preceding one and comes down the same distance.

When the ball is dropped from feet height

after first hit

new height

after second hit

new height

after third hit  

new height

after fourth hit

adding all distance

                                  feet

Hence the ball will travel   feet before it hits the surface fifth time.

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!