Pls help
In the diagram, AB = x cm, AE = (x + 2) cm, BD = (x + 6)cm.
CD= (x + 12) cm, angle ABE =90° and AE is parallel to CD. ABD and EBC are
straight lines
(1) Prove that the triangles in the diagram are similar.
(ii) Find the value of x.
C
(in) Find BC
x + 12
Ans: (ii) x=3
(11) BC = 12

it is probably the graph on the bottom right.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

not only in mathematics, scientific proof also are required in the other field of science. also maths proofs are of particular structure, containing steps and logics. so proving is like doing science, it is science. that's why it is important to prove. 

an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value