Given circle O, angle A has a measure of 36° and the radius is 10 cm, find the area of sector BOC.

The area of the sector BOC is A' = 31.4

Step-by-step explanation:

Radius of the circle = 10 cm = 0.1 m

Angle of sector = 36°

Area of the circle A =

A = 3.14 × = 0.0314

Now area of the sector BOC is

A' = 0.00314   = 31.4

Therefore the area of the sector BOC is A' = 31.4

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6