The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4764 miles, with a variance of 193.600.
If he is correct, what is the probability that the mean of a sample of 34 cars would differ from the population mean by greater than 149 miles?
Round your answer to four decimal places

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

source:  

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation:

answer: c

step-by-step explanation