Let v⃗ 1=⎡⎣⎢⎢⎢0.50.50.50.5⎤⎦⎥⎥⎥, v⃗ 2=⎡⎣⎢⎢⎢0.50.5−0.5−0.5⎤⎦⎥⎥⎥, v⃗ 3=⎡⎣⎢⎢⎢0.5−0.5−0.50.5⎤⎦⎥⎥⎥. v→1=[0.50.50.50.5], v→2=[0.50.5−0.5−0.5], v→3=[0.5−0.5−0.50.5]. find a vector v⃗ 4v→4 in r4r4 such that the vectors v⃗ 1v→1, v⃗ 2v→2, v⃗ 3v→3, and v⃗ 4v→4 are orthonormal.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

4.

step-by-step explanation:

it have the same area.brainliest

first the equation needs to be simplified. so the equation would now look like:   52-24+11

then you multiply.

and when you multiply, you will get the answer of 39.