A marching band is arranged in rows of 7 the first row has 3 band members and each row after the first has 2 more band members than the row before it write a rule for the number of band members in the nth row. Then find the total number of band members.

= 1+2n and 63

Step-by-step explanation:

the question belongs to arithmetic sequence and can be determined by the formula

= a1 + d (n-1)

Let " " represents the number of band members in the nth row

and 'd' represents the common difference.( as stated each row  has 2 more band members than the row before it)

therefore, d=2

'a1' represents first row that has three members. So, a1 = 3

->Rule for nth term will be:

= 3 + 2(n-1)

= 3 + 2n -2

= 1+2n

-> In order to find total number of band members ''

Let represent total number in n rows

We'll use the formula, i.e  = n/1 ( +  )

where, n is the number of terms, is the first term and is the last term

So,

n=7

= 1 + 2(7)= 15

=> = 7/2 (3 + 15)

= 63

The total number of band members are 63

20

step-by-step explanation:

idk

step-by-step explanation:

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