The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm cubed of water.
Find the percent of the cup that is filled with water after 3 seconds.
The dimensions of the cup are as follows: Radius: 4 cm Height: 7 cm

The answer to your question is  29.79 %

Step-by-step explanation:

Data

time = 2 s  = 70 cm³

time = 3s    = ? cm³

radius = 4 cm

height = 7 cm

Process

1.- Calculate the volume of the cup

Volume = πr²h

-Substitution

Volume = (3.14)(4)²(7)

             = 351.68 cm³

2.- Calculate the percent filled after 2 seconds

                     352.68 cm³   100 %

                        70 cm³          x

                              x = (70 x 100)/ 352.68

                              x = 19.84 %

3.- Calculate the percent filled after 3 seconds

                       2 seconds 19.84%

                       3 seconds  x

                                     x = (3 x 19.84)/2

                                      x = 29.79 %

4.- Conclusion

After 3 seconds the cup will be 29.79 % filled.

da freeck kinda math is this just drop out

step-by-step explanation: