Is(2, 5)asolutiontotheinequality 2x + 3y ≥ 20 ?

no

Step-by-step explanation:

2x + 3y ≥ 20

Substitute the point (2,5) in for x and y and see the inequality is true

2(2) +3(5) ≥ 20

4 + 15 ≥ 20

19 ≥ 20  

This is not true, so (2,5) is not a solution

Steps to solve:

2x + 3y ≥ 20; x = 2, y = 5

~Substitute

2(2) + 3(5) ≥ 20

~Simplify

4 + 15 ≥ 20

~Simplify

19 ≥ 20

The inequality is NOT true. Therefore, (2,5) is NOT a solution to the inequality.

Best of Luck!

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

step-by-step explanation: