5 barrels catch rainwater in the schoolyard. Four barrels are the same size, and the fifth barrel holds 10 liters of water. Combined, the 5 barrels can hold at least 200 liters of water. Write an inequality whose solution is the possible size of each of the 4 barrels.

How are these two problems similar? How are they different?

The volume each of the four barrels of the same size will be at least 47.5 liters.

Step-by-step explanation:

Let the volume of each of the four barrels is v liters.

Now, the amount of water that can be held in the fifth barrel is 10 liters. The total capacity of holding water for the 5 barrels combines is at least 200 liters.

So, from the above-given information, we can write the inequality to determine the volume of each of the four barrels will be  

10 + 4v ≥ 200

Solving this we get,

4v ≥ 190

⇒ v ≥ 47.5

Therefore, the volume each of the four barrels of the same size will be at least 47.5 liters. (Answer)

been looking for the answer havent been able to find it   but good luck with it