The lifespans of lizards in a particular zoo are normally distributed. The average lizard lives 3.1 1 years; the standard deviation is .06.
Use the empirical rule (68- 95- 99.7 percent) to estimate the probability of a lizard living less than 2.5 years. PLS HELP

16%

Step-by-step explanation:

Calculate the z score.

z = (x − μ) / σ

z = (2.5 − 3.1) / 0.6

z = -1

According to empirical rule, 68% is between -1 and +1 standard deviations.

P(-1 < Z < 1) = 68%

Since normal distributions are symmetrical, 34% is between -1 and 0 standard deviations.

P(-1 < Z < 0) = 68% / 2 = 34%

And since 50% is less than 0 standard deviations, that means 16% is less than -1 standard deviations.

P(Z < -1) = 50% − 34% = 16%

i really dont know

step-by-step explanation:

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step-by-step explanation: