Solve for x in the equation x squared + 4 x minus 4 = 8.
x = –6 or x = 2
x = negative 2 plus-or-minus 2 StartRoot 2 EndRoot
x = –2 or x = 6
x = 2 plus-or-minus 2 StartRoot 2 EndRoot

We want to solve the given quadratic equation, we will see that the solutions are: x = 2 and x = -6

So the given equation is:

We can rewrite it as:

The solutions are given by the Bhaskara's formula, it gives:

So the two solutions are:

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Step-by-step explanation:

x² + 4x − 4 = 8

x² + 4x − 12 = 0

(x + 6) (x − 2) = 0

x = -6 or x = 2

i think it would be c

mark brainliest if im right

step-by-step explanation: