Suppose that the functions q and r are defined as follows.
q (x) = 2x+2
r(x) = x² +1
Find the following.
(r •q)(-3) = 0

(q •r)(-3) = 0

The function (r •q)(-3) =(q •r)(-3)  and they are equal to -40

Given the following functions

q(x) = 2x+2

r(x) = x² +1

Taking the product

q(x)*r(x) = (2x+2)(x² +1)

Note that according to the communatative law, (r •q)(x) = (q •r)(x)

(r •q)(-3) =(q •r)(-3) = (2(-3)+2)((-3)² +1)

(r •q)(-3) =(q •r)(-3) = (-4)(9+1)

(r •q)(-3) =(q •r)(-3) = -4(10)

(r •q)(-3) =(q •r)(-3) =-40

Hence the function (r •q)(-3) =(q •r)(-3)  and they are equal to -40

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Given:

The two functions are ,

We need to determine the value of and

Value of :

Let us determine the value of  

Now, substituting x = -3, we get;

Thus, the value of is 17

Value of :

Let us determine the value of

Substituting x = -3, we get;

Thus, the value of is 22.

it should be a.

hope it

yeah i know the problem you need. i am taking it right now. the answer is step 3

~mickey