George tells you that when variables are in the denominator, the equation becomes unsolvable. "there is a value for x that makes the denominator zero, and you can't divide by zero," george explains. using complete sentences, demonstrate to george how the equation is still solvable.

The equation can still be solved but it should be stated clearly at what value of would the equation be undefined. For instance, you have an expression,

1/x+2

When x is equal to -2, the denominator will be 0 resulting to an undefined solution. The value of x here can be any real number except -2.

Where is the diagram?