Solve the problem.
3) At a track meet with 135 participants, 25 participate in jumping events, of these jumpers are female, and
of the total participants are female. What is the probability that a participant chosen at random is a jumper,
given that the person is a female?

1/9 is the probability that a participant chosen at random is a jumper,  given that the person is a female.

Step-by-step explanation:

In the question, some of the data are missing.

So the correct question is "At a track meet with 135 participants, 25 participate in jumping events, 1/5 of these jumpers are female, and  1/3 of the total participants are female. What is the probability that a participant chosen at random is a jumper,  given that the person is a female?"

Given,

The number of females in the track = 1/3 of the total participants

⇒ 1/3 (135)

⇒ 45 female participants.

The number of females in jumping event = 1/5 of the jumpers

⇒ 1/5 (25)

⇒ 5 female jumpers.

To find the probability of a female jumper participant :

P(a female jumper) = No.of female jumpers / Total female participants.

⇒ 5 / 45

⇒ 1 / 9.

∴ 1/9 is the probability that a participant chosen at random is a jumper,  given that the person is a female.

the answer will be the last one

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.