An airline wants to evaluate the depth perception of its pilots over the age of fifty. A random sample of n = 14 airline pilots over the age of fifty are asked to judge the distance between two markers placed 20 feet apart at the opposite end of the laboratory. Assume we don’t know the population standard deviation. The sample data listed here are the pilots’ error (recorded in feet) in judging the distance.

2.9 2.6 2.9 2.6 2.4 1.3 2.3
2.2 2.5 2.3 2.8 2.5 2.7 2.6

Is there evidence that the mean error in depth perception for the company’s pilots over the age of fifty is greater than 2.1? Use α = 0.05 and software to get the results, and paste in the appropriate output. (Note: make sure you write the hypotheses, the test statistic, P-value and conclusions in terms of the problem.) What is the 90% confidence interval for the mean error in depth perception?

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

answer: the correct answer is -32

step-by-step explanation:

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.