Question 4
1 pts
The stopping distance d of an automobile is directly proportional to the square of its
speed s. On one road, a car requires 75 feet to stop from a speed of 30 miles per hour.
How many feet does the car require to stop from a speed of 48 miles per hour on the
same road?

The car requires 192 ft to stop from a speed of 48 mph

Explanation:

Given:

Speed, u = 30 mph

Stopping distance, d = 75 feet

The stopping distance d of a car after the brakes are applied varies directly as the square of the speed, u

So,

d = k (u)²

On substituting the value:

75 = k (30)²

k =

Speed, u₂ = 48 mph

d₂ = ?

d₂ = k (u₂)²

On substituting the values we get:

d₂ =

d₂ = 192 ft

4.6875 pounds

step-by-step explanation:

y > 1/3x

y < = -x + 4

hope this : )