Find the distance between the pair of points (2,6) and (7,-4)

The distance is 5sqrt5 units

Step-by-step explanation:

Use distance formula: sqrt((7-2)^2+(-4-6)^2)

sqrt((5)^2+(-10)^2)

sqrt(25+100)

sqrt(125)

5sqrt5

So the answer is 5sqrt5 units

5

Step-by-step explanation:

Lets use the distance between points formula:

x1=2

x2=6

y1=7

y2=-4

=5

5 is the distance between the two points

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94