A teacher has 30 students in a classroom. She has 6 seats in the front row. How many ways can she arrange her students to sit in the front row?

427,518,000  ways.

Step-by-step explanation:

-This is a permutation problem of the form:

Where n is the number of objects and r is the number of objects taken at a time.

-Permutation is a linear order or sequence arrangement of a set's elements.

-The number of ways can therefore be calculated as:

Hence, the 30 students can be arranged in 427,518,000 different ways.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116