A large national bank charges local companies for using theirservices. A bank official reported the results of a regressionanalysis designed to predict the bank's charges(Y)—measured in dollars per month—for servicesrendered to local companies. One independent variable used topredict the service charge to a company is the company's salesrevenue (X)—measured in millions of dollars. Datafor 21 companies who use the bank's services were used to fit themodel:

E(Y) = β0 +β1X

The results of the simple linear regression are provided below.

= -2,700 + 20X, SYX = 65, two-tailed p value = 0.034(for testing β1)

Interpret the estimate of σ, thestandard deviation of the random error term (standard error of theestimate) in the model.
A)About 95% of the observed service charges equal their correspondingpredicted values.
B)About 95% of the observed service charges fall within $65 of theleast squares line.
C)For every $1 million increase in sales revenue, we expect a servicecharge to increase $65.
D)About 95% of the observed service charges fall within $130 of theleast squares line.

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

a

step-by-step explanation:

0 is its x and y coordinate

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.