Circle A is located at (6, 5) and has a radius of 3 units. What is the equation of a line that is tangent to circle A from point C (9, 8)? y = −x + 14 x = 9 y = x − 1 x = 4

y = -x + 17

Step-by-step explanation:

Gradient of the normal:

(8-5)/(9-6) = 3/3 = 1

Gradient of the tangent:

-1/1 = -1

y = -x + c

8 = -9 + c

c = 17

y = -x + 17

The answer is x=9

b. x- 48 =120

step-by-step explanation:

answer is 1

step-by-step explanation: