Find the equation of the circle that has center (-1,1) and passes through (-5,6)

circle equation for each pair of points can be expressed as:

(x1−h)2+(y1−k)2=(x2−h)2+(y2−k)2,

we get : (x1−h)2−(x2−h)2=(y2−k)2−(y1−k)2,

(x1−x2)(x1+x2−2h)=(y2−y1)(y2+y1−2k)

Introducing a1=(x1−x2),a′1=(x1+x2),b1=(y2−y1),b′1=(y2+y1)

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: