URGENT!!
In the figure below, ΔABC ≅ ΔDEF. Point C is the point of intersection between segment AG and segment BF, while point E is the point of intersection between segment DG and segment BF.

The figure shows a polygon comprised of three triangles, ABC, CEG, and DFE.

Prove ΔABC ∼ ΔGEC. (10 points)

Good morning ☕️

Step-by-step explanation:

NOTE: The idea here is this:

If two pairs of corresponding angles in ΔABC and  ΔGEC are congruent, then

ΔABC ∼ ΔGEC.

since ΔABC ≅ ΔDEF then ∠ABC and ∠DEF are congruent (1)

and since the pair of angles ∠DEF and ∠CEG is vertical then ∠DEF and

∠CEG are congruent (2)

from the relations (1) and (2) we conclude that ∠ABC and ∠CEG are congruent  (3)

now, the pair of angles ∠ACB and ∠ECG is vertical then ∠ACB and

∠ECG are congruent (4)

NOTE + (3) + (4) prove that ΔABC is similar to  ΔGEC

:)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

step-by-step explanation:

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