In the year 2008, a company made $4.9 million in profit. For each consecutive year after that, their profit increased by 12%. How much would the company's profit be in the year 2011, to the nearest tenth of a million dollars?

The profit of the company in 2011 is $ 6.89 million

Step-by-step explanation:

Given data

In 2008 profit made by the company (P) = $ 4.9 million

Increase in profit of the company R = 12 % yearly

Now the profit of the company in 2011 is given by

Here P =  $ 4.9 million

R = 12 % = 0.12

T = 3 years

Thus  the profit of the company in 2011 is

= 6.89 million dollars

Therefore the profit of the company in 2011 is $ 6.89 million

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: