Of the members of the Spring Lake Bowling Lanes, 57% have a lifetime membership
and bowl regularly (three or more times a week). If 70% of the club members bowl
regularly, find the probability that a randomly selected member is a lifetime member,
given that he or she bowls regularly.
a) 0.056
b) 0.814
c) 0.533
d) 0.538

The probability that a randomly selected member is a lifetime member,  given that he or she bowls regularly is 0.814, option b

Step-by-step explanation:

Let "M" denotes the event that a club member has a lifetime membership and "B" be denotes the event that the club member bowls.

57% of the members have lifetime membership and bowl regularly. This means, the probability that a randomly selected member has a lifetime membership and bowls regularly =

70% of the club members bowl. This means, the probability that a randomly chosen member bowls = P(B) = 70% = 0.70

We have to find the probability that a randomly selected member is a lifetime member,  given that he or she bowls regularly. This is conditional probability which can be expressed mathematically as P(M | B)

The formula to calculate the conditional probability is:

So, the formula for  our case will be:

Using the values in this formula we get:

This means, the probability that a randomly selected member is a lifetime member,  given that he or she bowls regularly is 0.814

sorry not sure

step-by-step explanation: