What are the zeros of the quadraic function?
f(x)=2x^2 + 10x – 12

The zeros are 1 and -6

Step-by-step explanation:

f(x)=2x^2 + 10x – 12

Set the equation equal to zero

0 =2x^2 + 10x – 12

Divide each side by 2

0/2=2/2x^2 + 10/2x – 12/2

0 = x^2 +5x -6

Factor

What 2 numbers multiply to -6 and add to 5

6*-1 = -6

6-1 =5

(x+6) (x-1) =0

Using the zero product property

x+6 =0   x-1=0

x=-6  x=1

y > 1/3x

y < = -x + 4

hope this : )

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: