Triangle ABC where A(1,3), B(3,1) and C(5,4) was mapped onto A'(-3,3),
B'(-1,5) and C'(-4,7)
(a) Plot both the object and its image on the same axes and describe fully the
transformation performed.
(b)lf triangle AB'C' is further translated to triangle A"B"C" by vector T=
find
the coordinates of the vertices of the last image.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]