30 Points ill mark brainiest, please help.

Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula?

Got it!

The given Quadratic Equation is:

-2= -x+x^2-4

i.e, x^2-x-2=0

now we have to compare it to the form ax^2+bx+c=0

by comparing we got a=1,b= -1 and c= -2

in other way around ,when coefficient of x^2 taken as negative then the sign of a,b&c will change ,

as a= -1, b=1 and c=2

✌️:)

a = 1, b = -1, c = -2

Or,

a = -1, b = 1, c = 2

Step-by-step explanation:

–2 = –x + x² – 4

x² - x - 4 + 2 = 0

x² - x - 2 = 0

a = 1, b = -1, c = -2

Or,

–2 = –x + x² – 4

-x² + x - 2 + 4 = 0

-x² + x + 2 = 0

a = -1, b = 1, c = 2

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

the answer is c 150

step-by-step explanation: