A line had a slope of -3 and a y-intercept if 3. what is the x-intercept of the line?

The answer to your question is 1

Step-by-step explanation:

Data

slope = m = -3

y-intercept = 3

Process

1.- Find the equation of the line in the slope-y-intercept form

                  y = mx + b

-Substitution

                  y = -3x + 3

2.- Find the x intercept

-If y = 0

                 0 = -3x + 3

               -3 = -3x

               -3/-3 = x

                  x = 1

-The x-intercept is 1

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

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step-by-step explanation: