A bag contains 5 red marbles, 6 blue marbles and 3 green marbles. If three marbles
are drawn out of the bag, what is the exact probability that all three marbles drawn
will be red?

.0274725275% chance

Step-by-step explanation:

the total number of marbles is 14, so you take the 5 red marbles and put it over 14 for the odds of the first marble being red, then subtract 1 from the numerator and the denominator until you have the probability of all three marbles being red, multiply the fractions for the final probability, it should look like this

5/14*4/13*3/12(3/12 simplifies to 1/4) so,

5/14*4/13*1/4= .0274725275

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )