WILL GIVE BRAINLIEST
The length of a rectangular frame is represented by the expression 2x + 8, and the width of the rectangular frame is represented by the expression 2x + 6. Write an equation to solve for the width of a rectangular frame that has a total area of 160 square inches.
4x2 + 32x + 48 = 0
4x2 + 28x − 112 = 0
2x2 + 32x − 112 = 0
x2 + 12x + 48 = 0

B. 4x^2=28x-112=0.

Step-by-step explanation:

Using area=length*width, 160=(2x+8)(2x+6).

Expanding, (2x+8)(2x+6)=4x^2+16x+12x+48.

Setting this equal to 160, 160=4x^2+28x+48, or 4x^2+28x-112=0.

line or a linear equation graph

step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: