Linear function A and linear function B both have the same input values as shown below. Why will the output values for linear
function A always be different than the corresponding output values for linear function B?
Linear Function A
Linear Function B
3
1
NAS
38
on
11
T
7
199
15
12
16
20
The initial values of the two functions are different, and the rates of change of the two functions are also different.
The initial values of the two functions are different, and the rates of change of the two functions are the same.
The initial values of the two functions are the same, and the rates of change of the two functions are different.
The initial values of the two functions are the same, and the rates of change of the two functions are also the same.
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step-by-step explanation:

just copy and paste it.

visit this site for a tutorial ʖ-tutorial-flash-cards/

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

↓↓↓↓↓↓↓↓↓

step-by-step explanation:

this is a parabola.