The vertex form of a quadratic function is f(x) = a(x-h)2 + k. What is the vertex of each function?

see below

Step-by-step explanation:

f(x) = a(x-h)^2 + k

Where (h,k) is the vertex

f(x) = 9(x-5)^2 + 6.  has a vertex of (5,6)

f(x) = 6(x- -9)^2  + -5  has a vertex of (-9, -5)

f(x) = 9(x- -5)^2  + -6  has a vertex of (-5, -6)

f(x) = 5(x- 6)^2  + 9  has a vertex of (6, 9)

f(x) = 6(x- 5)^2  + -9  has a vertex of (5, -9)

1) (5,6)

2) (-9,-5)

3) (-5,-6)

4) (6,9)

5) (5,-9)

Step-by-step explanation:

In a(x- h)² + k

Vertex is (h,k)

For h:

Equate the square bracket to 0

(x - h) = 0

x = h

For k:

Just pick the constant outside the square

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!