There are 3 paper clips and 5 erasers in a paper sack if 2 items are drawn at random without replacement what is the probability that onwme will draw a paper clip and then an eraser

Step-by-step explanation:

This is a probability event that expresses the likelihood of an event to occur.

   Number of paper clips in sack = 3

    Number of erasers in sack  = 5

Problem: Probability that one will draw a paper clip and then an eraser?

 These are two mutually exclusive events.

   Total number of paper in sack  = 3 + 5  = 8

Pr(drawing paper clip) =

   without replacement suggests that the total number of paper in sack will reduce by 1 to 7;

 Pr(drawing eraser)  =

So:

   Pr(paper clip and eraser ) =    =

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.