A square base of a pyramid has the dimensions 5 yards
by 5 yards. The height of one of the triangular faces is 12
yards. How can you find the surface area of the pyramid?

145 yd²

Step-by-step explanation:

There will be dour triangular faces. For a triangle, area is given as

A=½bh where b is base and h is height. The base will be 5 yards and h is 12 yards hence for one triangular face, area will be ½*5*12=30 yd²

Since they are four similar triangles, area of triangular faces will be 30*4=120 yd²

The surface area of a square base is given by

A=a*a=a² where a is the dimension of one side. Given that the meaurement is 5 yards then A=5²=25 yd²

Total area will be the sum of triangular and square faces hence 120+25=145 yd²

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