**HELP ASAP PLZ ;-;**
Let
f(x)=(x^2+3x-4)
and
g(x)=(x+4)
1. Find f*g and state the domain
2. Find f/g and state the domain

1. (x^3+7x^2+8x-16) ; domain: R (all real number)

2. (x-1) ; domain: R-(-4) {all real number except (-4)

Step-by-step explanation:

f*g= f(x) and g(x)

i.e, f*g= (x^2+3x-4)(x+4)

i.e, f*g= x^3+3x^2-4x+4x^2+12x-16

i.e, f*g=x^3+7x^2+8x-16

it's domain is R, i.e, all real number!

f/g=(x^2+3x-4)/(x+4)

i.e, f/g={(x+4)(x-1)}/4

i.e,f/g=x-1

it's domain is all real number,except the number at which (x+4) becomes 0, i.e, x= (-4), -4 is not in domain!

✌️;)

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: